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X(1), X(3), X(4), X(13), X(14), X(15), X(16), X(30), X(74), X(370), X(399), X(484), X(616), X(617), X(1138), X(1157), X(1263), X(1276), X(1277), X(1337), X(1338), X(2132), X(2133), X(3065), X(3440), X(3441), X(3464), X(3465), X(3466), X(3479), X(3480), X(3481), X(3482), X(3483), X(3484), etc. See Table 19 for other centers on K001 excenters; reflections of A, B, C in the sidelines of ABC; cevians of X(30) vertices of 6 equilateral triangles erected on the sides of ABC other points Ua, Ub, Uc, etc, below. See also Table 16 and Table 18. five mates of X(370). See also K143, K144, Q033 and Table 10 



The Neuberg cubic K001 is introduced in Neuberg's paper "Mémoire sur le tétraèdre" in Mémoires de l’Académie de Belgique, pp.1–70, 1884. The characterization given is related with properties of socalled "quadrangles involutifs" : 

K001 is sometimes called 21point cubic or 37point cubic in older literature. K001 is the isogonal pK with pivot X(30) = infinite point of the Euler line : it is the locus of point P such that the line PP* is parallel to the Euler line (P* isogonal conjugate of P). Hence it is a member of the Euler pencil, see Table 27. It follows that it is also the locus of P such that X(74), P, X(30)/P (Ceva conjugate) and X(2132), P, X(74)©P (crossconjugate) are collinear. X(74) is the isopivot (or secondary pivot) and X(2132) could be considered as a tertiary pivot. K001 is a circular cubic with singular focus X(110), focus of the Kiepert parabola. It is also the orthopivotal cubic O(X3) and C(0) = C(infty) in "On two Remarkable Pencils of Cubics of the Triangle Plane" (see Downloads page). The isotomic transform of K001 is K276. The inversive image of K001 in the circumcircle is Ki = K073. See also Inverses of Isocubics. See Table 20 for cubics anharmonically equivalent to K001. *** Related papers : Pairs and Triads of points on the Neuberg Cubic connected with Euler Lines and Brocard Axes 



Locus properties : (see also Z. Cerin's papers in bibliography)




Other properties : See details in Special Isocubics, §6.5 and also table 18. Ga, Gb, Gc are the vertices of the antimedial triangle. Denote by (Ha) the hyperbola passing through B, C, Ga, the reflection A' of A in the line BC, the reflection Ah of H with respect to the second intersection of the altitude AH with the circumcircle. The asymptotes of (Ha) make 60° angles with the sideline BC. (Hb) and (Hc) are defined similarly. See figure 1. (Ha), (Hb), (Hc) have three points Ua, Ub, Uc in common which lie :
The orthocenter of triangle UaUbUc is O and its circumcenter is L. Thus ABC and UaUbUc share the same Euler line. All rectangular hyperbolas passing through Ua, Ub, Uc, O are centered on the circle centered at X(550) with radius R (X(550) is the reflection of the nine point center X(5) in the circumcenter O). The isogonal conjugates Ua*, Ub*, Uc* of Ua, Ub, Uc , the midpoints Va, Vb, Vc of triangle Ua*Ub*Uc*, their isogonal conjugates Va*, Vb*, Vc* are nine other points on the Neuberg cubic. Notice that Va, Vb, Vc are the complements of Ua*, Ub*, Uc* respectively, these latter points lying on the circle C(O,2R). Thus the translation with vector OH maps the triangle UaUbUc to the triangle Ua*Ub*Uc*. Note that the lines Ua*Va*, Ub*Vb*, Uc*Vc* concur at X(399), the Parry reflection point. See figure 3. Hence we know the nine common points of the Neuberg cubic and the cubic which is its anticomplement : these are O, the Fermat points X(13) and X(14), the point at infinity X(30) of the Euler line, the three points Va, Vb, Vc and the circular points at infinity. At last, remark that all the cubics passing through A, B, C, Ga, Gb, Gc, Ua, Ub, Uc are equilateral cubics and the equilateral triangle formed by the asymptotes has always center O. The only K60+ is K0++ = K080 which is at the same time a central cubic. See also the related cubic K405 which contains Ua*, Ub*, Uc*. These points Ua, Ub, Uc are also the images under h(X4, 2) of the intersections (other than A, B, C) of the circumcircle and the Napoleon cubic K005. 

Other related points Ta on the lines : UbUc, HUa*, X74Va hence Ta = X30/Va, Tb, Tc likewise. Their isogonal conjugates : Ta*, Tb*, Tc*. 





Under the rotations with center O (resp. H) and angles +/2π/3, the Neuberg cubic is transformed into two other circular cubics K001+ and K001–. These two cubics generate a pencil of circular cubics passing through O (resp. H) and therefore having six other common points. This pencil contains the Neuberg cubic itself hence there are two equilateral triangles with center O (resp. H) inscribed in the Neuberg cubic. See the two figures below. 



A line passing through O meets the Neuberg cubic again at two points M, N (see property 8 above). Their isogonal conjugates M*, N* obviously lie on K001 and the line M*N* passes through X(399). It follows that these points M, N lie on a same circumconic passing through X(1138). The lines MN and M*N* intersect at S on the Stammler hyperbola and the midpoint P of MN is the inverse of S in the circumcircle. Hence P lies on the Stammler strophoid K038, the inversive image of the Stammler hyperbola in the circumcircle. The perpendicular bisector of MN is the tangent to the Kiepert parabola mentioned in property 8. The perpendicular bisector of M*N* envelopes another parabola which is the homothetic of the Kiepert parabola under h(X110, 3). The lines MN* and M*N meet at S* which lies on the Stammler quartic Q066, the isogonal transform of the Stammler hyperbola. *** Similarly, a line passing through H meets the Neuberg cubic again at two points M, N and the line M*N* passes through X(5667), the X(30)Ceva conjugate of X(4). The midpoint of MN lies on another strophoid K591 we shall call the KiepertNeuberg strophoid. *** These strophoids are both pedal curves of the Kiepert parabola. More information in K591, K592, K593. 



The osculating circle (Ca) at A to the Neuberg cubic passes through A, the traces of X(30) and X(526) on the sideline BC. Its center Oa lies on the line AX(110). (Cb), (Cc) and their centers Ob, Oc are defined similarly. The triangle OaObOc is perspective with • ABC at X(110), • the cevian triangle of X(476) at X(523), • the anticevian triangle of any point on the cubic K130 = pK(X6, X476). The locus of the perspector is the isogonal pK with pivot P = X(5)X(1117) /\ X(110)X(476) passing through the in/excenters, X(110), X(477), X(523), X(5663) and Oa, Ob, Oc. P lies on the anticomplement of the Steiner deltoid. Note that this cubic is tangent at X(523) to the line at infinity and tangent at X(110) to the circumcircle. See the analogous cubic K695 and further details in the page Q073. The third points Xa, Xb, Xc on the sidelines of OaObOc are the traces of X(523). The third points Ya, Yb, Yc on the sidelines of XaXbXc are the traces of the isogonal conjugate X(5663) of X(477) i.e. the lines XaYa, XbYb, XcYc are parallel to the line X(3)X(74)X(110). The perspectors of any two triangles ABC, IaIbIc, OaObOc, XaXbXc, YaYbYc and the cevian triangle of P are centers on the cubic. The last two common points with the Neuberg cubic are E1, E2 on the parallel at P to the Euler line. This cubic is also a pK with respect to OaObOc with pivot X(523), isopivot the infinite point X(5663) of the line X(3)X(74)X(110). Hence the tangents at Oa, Ob, Oc are parallel to this latter line. 



Let M be a point and C(M) its polar conic. C(M) is • a circle when M = X(110), the singular focus, • a rectangular hyperbola when M lies on the Euler line, the orthic line of the cubic, • a parabola when M lies on (P), the poloconic of the line at infinity, • an ellipse when M lies inside the (light blue) region delimited by (P) that contains X(110), • a hyperbola when M lies outside this same region. • the union of two lines when M lies on the hessian (H) of K001. *** (P) is a very remarkable hyperbola passing through X(476) and the vertices of the circumtangential triangle TaTbTc. It has two asymptotes making an angle of 60° thus its eccentricity is 2. X(110) is one of its foci and the related directrix is the Euler line. The tangent at X(476) is the real asymptote of the Neuberg cubic. Let P1, P2, P3, P4 be the poles of the line at infinity with respect to K001. (P) also passes through : • the 6 (orange) midpoints Mi of the complete quadrilateral P1P2P3P4, • the vertices Q1, Q2, Q3 of its (yellow) diagonal triangle. These vertices also lie on the hessian (H) of K001. The polar conics of Q1, Q2, Q3 with respect to K001 are three pairs of parallel lines. *** 

More generally, the poloconic of the line at infinity in any circular isogonal pK is an analogous hyperbola with eccentricity 2 passing through the vertices of the circumtangential triangle TaTbTc. 



K001 has three real prehessians (Ha), (Hb), (Hc) and each is related to a conjugation Fi on K001. These prehessians obviously contain the nine points of inflexion of K001. For example, Fa maps any point M on K001 to the center Ma of the (decomposed) polar conic (Ca) of M with respect to (Ha). It follows that M is associated to three points Ma, Mb, Mc on K001 such that : • the triangles ABC and MaMbMc are perspective at M*, the isogonal conjugate of M, • the tangents to K001 at M, Ma, Mb, Mc concur at M' on K001, • the polar conic C(M') of M' in K001 passes through M, M', Ma, Mb, Mc, • K001 is a pK with pivot M, isopivot M' with respect to the triangle MaMbMc. 

When M = X(30), the points Ma, Mb, Mc are the vertices of ABC and the lines AMa, BMb, CMc are the tangents at A, B, C to K001. When M = X(3), Ma, Mb, Mc are the reflections A', B', C' of A, B, C in the sidelines of ABC. M* = X(4) and M' = X(1157). This corresponds to the triangles #3 and #13 in Table 19 where other similar triangles are mentioned. See also Perspective Triangles inscribed in the Neuberg Cubic for proofs and further explanations. 



For any point P on the Neuberg cubic, recall that the Euler lines (Ea), (Eb), (Ec) of triangles PBC, PCA, PAB concur at M on the Euler line (E) of ABC. Conversely, for a given point M on (E), we seek points on the Neuberg cubic having this property. There are two such points P, Q on K001 which are the common points of the rectangular circumhyperbola (H) through M and the line (L) passing through X(399) and the reflection of O in M. Thus, the Euler lines of the six triangles PBC, PCA, PAB, QBC, QCA, QAB concur at M on (E). It follows that K001 can be seen as the locus of the intersections of (H) and (L) when M traverses (E). If X(399) is replaced by X(265), we obtain the cubic K638 whose isogonal transform is K639. Each of these two cubics have nine identified common points with the Neuberg cubic. Similarly, for a given point M on the Brocard axis, there are three points P1, P2, P3 such that the Brocard lines of the nine analogous triangles concur at M. More details here.

