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centers of the 3 Apollonian circles. vertices of the circumtangential triangle. other points described below. see other figures and a geometric construction below. 

Kjp = K024 is the only isogonal nK0 which is a nK60+. Its root is the Lemoine point K. Kjp is a good example of stelloid. See also K003 and Table 22. Kjp is mentioned in a paper by Shuzo TAKAMATSU and Shusaku OGINO : On Some Cubics connected with Simson lines Tohoku Math.J.43, p 99103 (1937). K024 is a member of the classes CL004, CL022 and CL026 of cubics. The hessian cubic of Kjp is K193. The isotomic transform of Kjp is K196. Locus properties (see also Table 8) M* being the isogonal conjugate of M, and Ma, Mb, Mc the second intersections of the cevian lines of M with the circumcircle (i.e. the vertices of the circumcevian triangle of M), Kjp is the locus of point M such that :
Locus properties related to Simson lines : Denote by sMa, sMb, sMc the Simson lines of Ma, Mb, Mc, and A1B1C1 the triangle bounded by these Simson lines (i.e. A1 = sMb /\ sMc, etc).


Points on the Kjp cubic The three real asymptotes are parallel to the sidelines of the Morley triangle and concur at G. Kjp intersects these asymptotes at A1, B1, C1 on the line L homothetic of the Lemoine axis under h(G,2/3). This is the satellite line of the line at infinity. It is also the trilinear polar of the isotomic conjugate of a^2(b^2+c^2)8a^2c^2: : , the homothetic of X(76) under h(G,3/2). Thus, Kjp meets its asymptototes on a parallel to the trilinear polar of its root. This is true for any nK0(X6, P) with P on the Grebe cubic K102. Kjp passes through the centers of the three Apollonian circles, intersections of the Lemoine axis with the sidelines of ABC. The common tangentials of these points and the vertices of ABC are the intersections A0, B0, C0 of the sidelines of the antimedial triangle GaGbGc and the trilinear polar L' of X(308), isotomic conjugate of the Brocard midpoint X(39). L' is the satellite line of the Lemoine axis. Kjp also contains the vertices Ta, Tb, Tc of the circumtangential triangle (see TCCT, p.166, §6.28). These are the isogonal conjugates of the infinite points of the Morley sidelines. Hence, their tangentials are the points A1, B1, C1. Kjp obviously contains the isogonal conjugates A0*, B0*, C0* of the points A0, B0, C0 (on the perpendicular bisectors of ABC, on the lines through the vertices of ABC and the corresponding Apollonian centers, on a circumconic C' through X99) and A1, B1, C1 (on a circumconic C through X99, X1576, X1634). From them it is easy to derive several other points on the cubic. See the figure below. 

Kjp meets the three Apollonius circles again at nine points which are the vertices of three equilateral triangles having their sidelines perpendicular to the sidelines of the circumtangential triangle. These points lie on the cevian lines of the vertices Ta, Tb, Tc of the circumtangential triangle. They also lie three by three on two triads of lines passing through the isodynamic points and making 60° angles with one another. Obviously, Kjp contains the isogonal conjugates of these nine points. Note that the Kjp cubic and the McCay cubic meet the three Apollonius circles at the vertices of three regular hexagons. Actually, since Kjp is a stelloid, one can find infinitely many equilateral triangles inscribed in the curve. 

Geometric construction of the Kjp cubic 

Let P be a point on the circumcircle (O) of ABC and let L(P) be the parallel at O to the Simson line of P. L(P) meets (O) at two points. The line AP meets the rectangular hyperbola passing through these two points, B and C at M, N on the Kjp cubic. Denote by M*, N* the isogonal conjugates of M, N. Obviously, MN and M*N* meet at A. The lines MN* and M*N pass through the center of the AApollonian circle. The lines MM* and NN* meet at S on the perpendicular bisector of BC and on the tangent at P to (O). If L(P) is given, P is the isogonal conjugate of any perpendicular to L(P). Note that the perpendicular at A to the line AP intersects the same rectangular hyperbola at two points on the McCay cubic. 

Hessian and prehessians 

The hessian of K024 is K193. K024 has three prehessians but one only P024 is real. This means that the hessian of P024 is K024. These three cubics generate a syzygetic pencil of cubics passing through the nine common inflexion points of K024. The prehessians have the same orthic line namely the Lemoine axis L. The polar conic of any point on L is a diagonal rectangular hyperbola passing through the in/excenters of ABC. With X(512) and X(669), we obtain the Stammler and Wallace hyperbolas represented on the figure. This gives a natural involution f on K024 that carries any point P to the center of the polar conic of P with respect to P024. The vertices T1, T2, T3 of the circumtangential triangle are the singular points of f. f swaps • A, B, C and the centers of the Apollonius circles , the Lemoine axis and the circumcircle, • any line through G and a rectangular hyperbola through O and T1, T2, T3. *** The poloconic of any line ∆ with respect to P024 is a conic tritangent to K024. If ∆ meets K024 at three points, the points of tangency are their images under f. If ∆ is tangent to K024 at M, the conic is surosculating K024 at f(M) and is tangent at K024 at the image of the tangential of M. If ∆ is an inflexional tangent at M to K024, the conic has a sextuple contact with K024 and f(M) is said to be a sextactic point. There are four lines for which the conic is a circle and the corresponding conics are four circles tritangent to K024 and tangent to the circumcircle of ABC. This is the Feuerbach theorem for the cubic K024. The four circles are analogous to the in/excircles and the circumcircle is analogous to the nine point circle. 
