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There are "officially" two Brocard triangles. Since the isogonal conjugates of their vertices are often present, we shall call them also Brocard triangles.

Brocard (first) triangle A1B1C1

A1 = (a^2 : c^2 : b^2) is the projection of K = X(6) on the perpendicular bisector of BC.

 

Brocard (second) triangle A2B2C2

A2 = (b^2 + c^2 - a^2 : b^2 : c^2) = (2 SA : b^2 : c^2) is the projection of O = X(3) on the symmedian AK.

 

Brocard (third) triangle A3B3C3

A3 = (b^2c^2 : b^4 : c^4) is the isogonal conjugate of A1. A3 lies on the A-cevian line of X(32), the 3rd power point.

 

Brocard (fourth) triangle A4B4C4 (sometimes called D-triangle)

A4 = (a^2 : b^2 + c^2 - a^2 : b^2 + c^2 - a^2) = (a^2 : 2 SA : 2 SA) is the isogonal conjugate of A2.

A4 is the projection of H = X(4) on the median AG.

 

A lot of interesting properties can be found in :

  • Lalesco T. : La géométrie du triangle, Gabay, Paris, 1987.
  • Honsberger, R. : Episodes in Nineteenth and Twentieth Century Euclidean Geometry, Washington, DC Math. Assoc. Amer., 1995.
  • Johnson, R. A. : Advanced Euclidean Geometry, Dover Publications Inc, Mineola, New York, 1960.

Similar triangles

TR1indir

A1B1C1 is directly similar to ?

A1B1C1 is indirectly similar to ABC and to the medial triangle.

TR2dir TR2indir

A2B2C2 is directly similar to the pedal triangle of X(23), the inverse of G in the circumcircle.

A2B2C2 is indirectly similar to the pedal triangle of the centroid G.

TR3dir TR3indir

A3B3C3 is directly similar to the antipedal triangle of Zd, a point with complicated coordinates.

A3B3C3 is indirectly similar to the pedal triangle of Zi, a point with complicated coordinates.

TR4dir TR4indir

A4B4C4 is directly similar to the pedal triangle of X(187), the inverse of K in the circumcircle.

A4B4C4 is indirectly similar to the antipedal triangle of the centroid G.

Perspective triangles

Two Brocard triangles are in general not perspective with two notable exceptions.

TR1TR2persp TR1TR3persp

A1B1C1 and A2B2C2 are simply perspective at G.

The axis of perspective is the line passing through X(99), X(110). This is the trilinear polar of the isotomic conjugate of X(115), the center of the Kiepert hyperbola.

A1B1C1 and A3B3C3 are triply perspective at X(384), Ω1 and Ω2.

The corresponding axes of perspective are the lines L0, L1 and L2.

L0 is the trilinear polar of X(385). L1 and L2 meet at X(694), the isogonal conjugate of X(385).

Loci related with perspective triangles

The following table gives the locus of point P such that one of the Brocard triangles is perspective with one of the usual triangles related to P. See Table6.

Some loci of corresponding perspectors are also given.

A1B1C1

A2B2C2

A3B3C3

A4B4C4

cevP

K322 = pK(X1916, X694)

K531 = pK(X3455, X67)

K532 = pK(X32 x X694, X694)

K533 = pK(X4 x X67, X4 x X67)

acvP

K128 = pK(X6, X385)

K534 = pK(X3, X524)

K128 = pK(X6, X385)

K535 = pK(X25, X468)

pedP

a conic through X(3), X(3098)

a cubic

a cubic

a cubic through O

apdP

K422 = pK(X6, ?)

K536, a circular cubic

K422 = pK(X6, ?)

K537, a circular cubic

ccvP

a quartic through X(1), X(76), X(694)

a quartic through X(6), X(2930)

a quartic through X(6), X(32)

a quartic through X(2), X(67)

cacP

a sextic through X(1), X(6)

a sextic through X(6)

a sextic through X(6)

a sextic through X(1), X(67)

refP

a cubic through X(3), X(511), X(2076)

a cubic through X(184)

a cubic

a cubic through X(935)

loci of perspectors

cevP

K020 = pK(X6, X384)

K538 = pK(X3, X141)

K020 = pK(X6, X384)

K539 = pK(X25, X427)

acvP

K020 = pK(X6, X384)

K538 = pK(X3, X141)

K020 = pK(X6, X384)

K539 = pK(X25, X427)

Cubics through Brocard related points

This section written with the collaboration of Chris van Tienhoven.

The table below sums up all the catalogued cubics passing through the Brocard points Ω1, Ω2 and/or the vertices of some Brocard triangle.

cubic

type / name

Ω1, Ω2

A1B1C1

A2B2C2

A3B3C3

A4B4C4

X(i) on the cubic for i =

K012

isotomic nK / Tucker-Brocard

6, 76, 880, 882

K017

isogonal nK0 / Brocard 1

2, 6, 99, 512

K018

isogonal nK0 / Brocard 2

2, 6, 13, 14, 15, 16, 111, 368, 524

K019

isogonal focal nK0 / Brocard 3

98, 511

K020

isogonal pK / Brocard 4

1, 3, 4, 32, 39, 76, 83, 194, 384, 695, 2896, 3224, 3491 upto 3503

K021

isogonal pK / Brocard 5

1, 99, 512, 2142, 2143

K022

nK / Brocard 6

3, 4, 110, 525

K023

orthopivotal cubic / Brocard 7

4, 13, 14, 30, 1316

K083

see note below

368

K153

- / Brocard 8

6

K166

isogonal focal nK / Brocard 9

3, 4, 1316, 2698, 2782

K248

isogonal nK / Brocard-Steiner focal

187, 538, 671, 729

K326

isogonal pK / Brocard 10

1, 39, 83

K359

isogonal focal nK / Brocard strophoid

1, 1083

K444

- / K(X32)

4, 32, 194

K512

- / Brocard-van Tienhoven

3, 76, 3224

K538

pK

6, 69, 141, 1176, 2916

K539

pK

2, 25, 251, 427

K012*

nK / -

2, 32, 881

K023*

isogonal transform of Brocard 7

3, 15, 16, 74

K545

K0+ / Brocard 11

76

K546

- / Brocard 12

32

K547

- / Brocard 13

39, 76

K548

- / Brocard 14

76, 2896

K549

K+ / Brocard 15

K550

- / Brocard 16

76

K551

- / Brocard 17

76

K552

- / Brocard 18

76, 99

K553

acnodal cubic / Brocard 19

2, 76

Notes :

K083-A-B-C are the three equibrocardian focals. Each cubic contains only one vertex of the second Brocard triangle.

K012* is the isogonal transform of K012 namely nK(X32, X6, X2).

***

Circum-cubics passing through the vertices of two Brocard triangles

In general, there is one and only one such cubic (most of the time quite uninteresting) with the notable exception of the triangles A1B1C1 and A3B3C3.

In this latter case, one can find a pencil of cubics generated by K017 and K020. This pencil is stable under isogonal conjugation i.e. the isogonal transform of the cubic passing through a point P is the cubic passing through P*.

***

Circum-cubics passing through the Brocard points and the vertices of one Brocard triangle

In all four cases, these cubics form a pencil and must contain a nineth (fixed) point F.

• with A1B1C1, F = X(76) and the pencil is generated by K012 and K512.

• with A3B3C3, F = X(32) and the pencil is generated by K444 (the isogonal transform of K512) and the isogonal transform of K012 namely nK(X32, X6, X2).

Note that the isogonal transform of a cubic of the former pencil is a cubic of the latter pencil and vice versa.

• with A2B2C2 and A4B4C4, the corresponding points F do not appear in the present version of ETC but the note above remains true.

***

Other remarkable circum-cubics

The cubics K019, K021, K023 are all circular cubics of a same pencil with the same focus X(98) and passing through the Brocard points. The real asymptote passes through X(99) and the orthic line passes through X(3). It follows that the polar conic of X(3) in each cubic is a rectangular hyperbola whose center is a point on the circle with diameter X(4)-X(147). Once again, this pencil is stable under isogonal conjugation and contains the isogonal transform of K023.

See figure below and also CL056.

K019K021K023